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x^2+8x=22.5
We move all terms to the left:
x^2+8x-(22.5)=0
We add all the numbers together, and all the variables
x^2+8x-22.5=0
a = 1; b = 8; c = -22.5;
Δ = b2-4ac
Δ = 82-4·1·(-22.5)
Δ = 154
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{154}}{2*1}=\frac{-8-\sqrt{154}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{154}}{2*1}=\frac{-8+\sqrt{154}}{2} $
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